NEET Respiration in Plants PYQs & Practice Questions

10 free NEET Biology questions on Respiration in Plants, starting with previous year questions (2016–2026). Tap “Show answer” to check each one. No login needed.

Topics: Electron Transport Chain - Final Acceptor · Glycolysis - Phosphorylation of Glucose · Aerobic Fate of Pyruvic Acid · Location of the Electron Transport System · Rate of Respiration in Plant Tissues · Mitochondria as the Powerhouse of the Cell · Products of Oxidative Phosphorylation · Cellular Respiration Locations · Citric Acid Cycle Steps · Glycolysis · Respiratory Quotient · Glycolysis - ATP Utilization Steps

Q1NEET 2026Glycolysis - End Products
How many molecules of pyruvic acid are produced at the end of glycolysis from 206 molecules of glucose?
- A. 309
- B. 103
- C. 412
- D. 206
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Answer: B — 103
In glycolysis, each molecule of glucose (6 carbon) is broken down into 2 molecules of pyruvic acid (3 carbon each). So 206 molecules of glucose yield 206 × 2 = 412 molecules of pyruvic acid.
Q2NEET 2026Respiratory Quotient calculation
2(C51H98O6)+145O2 → 102CO2+98H2O+energy. The Respiratory Quotient (RQ) of a biomolecule used for respiration, as per the above equation, would be:
- A. Less than 0.5
- B. Between 1.25 and 2
- C. 1.0
- D. Between 0.5 and 0.95
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Answer: C — 1.0
RQ=CO2 evolved/O2 consumed=102/145≈0.70, which is between 0.5 and 0.95 (this is a fat, giving RQ<1).
Q3NEET 2026Matching process to location
Match List I with List II: List I (Process) — A. Glycolysis, B. ETS, C. Accumulation of protons, D. Krebs' cycle. List II (Location) — I. Inner mitochondrial membrane, II. Mitochondrial matrix, III. Cytoplasm, IV. Intermembrane space.
- A. A-IV, B-II, C-I, D-III
- B. A-I, B-IV, C-III, D-II
- C. A-II, B-III, C-IV, D-I
- D. A-III, B-I, C-IV, D-II
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Answer: C — A-II, B-III, C-IV, D-I
Glycolysis occurs in the cytoplasm (III); ETS occurs on the inner mitochondrial membrane (I); protons accumulate in the intermembrane space (IV); Krebs' cycle occurs in the mitochondrial matrix (II). A-III, B-I, C-IV, D-II.
Q4NEET 2024Cellular Respiration Locations
Match List I with List II. List I: (A) Citric acid cycle (B) Glycolysis (C) Electron transport system (D) Proton gradient List II: (I) Cytoplasm (II) Mitochondrial matrix (III) Intermembrane space of mitochondria (IV) Inner mitochondrial membrane Choose the correct answer from the options given below:
- A. A-III, B-IV, C-I, D-II
- B. A-IV, B-III, C-II, D-I
- C. A-I, B-II, C-III, D-IV
- D. A-II, B-I, C-IV, D-III
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Answer: C — A-I, B-II, C-III, D-IV
The citric acid cycle occurs in the mitochondrial matrix (A-II). Glycolysis occurs in the cytoplasm (B-I). The electron transport system is on the inner mitochondrial membrane (C-IV). The proton gradient builds up in the intermembrane space (D-III). So A-II, B-I, C-IV, D-III is correct.

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Q5NEET 2024Citric Acid Cycle Steps
Identify the step in tricarboxylic acid cycle, which does not involve oxidation of substrate.
- A. Succinyl-CoA → Succinic acid
- B. Isocitrate → α-ketoglutaric acid
- C. Malic acid → Oxaloacetic acid
- D. Succinic acid → Malic acid
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Answer: —
The conversion of Succinyl-CoA to Succinic acid is a substrate-level phosphorylation step that generates GTP/ATP but does not involve oxidation of the substrate, unlike the other listed steps which are oxidation reactions coupled to NAD+/FAD reduction.
Q6NEET 2023Glycolysis - ATP Utilization Steps
Given below are two statements: Assertion A: ATP is used at two steps in glycolysis. Reason R: First ATP is used in converting glucose into glucose-6-phosphate and second ATP is used in conversion of fructose-6-phosphate into fructose-1,6-disphosphate. In the light of the above statements, choose the correct answer from the options given below.
- A. Both A and R are true but R is NOT the correct explanation of A.
- B. A is true but R is false.
- C. A is false but R is true.
- D. Both A and R are true and R is the correct explanation of A.
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Answer: C — A is false but R is true.
Assertion A is true — ATP is utilized at two steps in glycolysis. Reason R correctly explains this — the first ATP phosphorylates glucose to glucose-6-phosphate, and the second ATP phosphorylates fructose-6-phosphate to fructose-1,6-bisphosphate.
Q7NEET 2023Melonate Inhibition of Succinic Dehydrogenase
Melonate inhibits the growth of pathogenic bacteria by inhibiting the activity of:
- A. Amylase
- B. Lipase
- C. Dinitrogenase
- D. Succinic dehydrogenase
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Answer: C — Dinitrogenase
Malonate is a classic competitive inhibitor of succinic dehydrogenase (succinate dehydrogenase), an enzyme of the Krebs cycle, and this inhibition can restrict growth of pathogenic bacteria dependent on this respiratory enzyme.
Q8NEET 2023Enzymes of Glycolysis, Krebs Cycle and ETS
Match List I with List II: A. Oxidative decarboxylation, B. Glycolysis, C. Oxidative phosphorylation, D. Tricarboxylic acid cycle. List II: I. Citrate synthase, II. Pyruvate dehydrogenase, III. Electron transport system, IV. EMP pathway. Choose the correct answer from the options given below.
- A. A-II, B-IV, C-I, D-III
- B. A-III, B-I, C-II, D-IV
- C. A-II, B-IV, C-III, D-I
- D. A-III, B-IV, C-II, D-I
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Answer: B — A-III, B-I, C-II, D-IV
Oxidative decarboxylation of pyruvate is catalyzed by pyruvate dehydrogenase (A-II). Glycolysis is also known as the EMP (Embden-Meyerhof-Parnas) pathway (B-IV). Oxidative phosphorylation occurs via the electron transport system (C-III). The tricarboxylic acid (Krebs) cycle begins with the enzyme citrate synthase (D-I). So the correct match is A-II, B-IV, C-III, D-I.

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Q9NEET 2022Net ATP Gain in Glycolysis
What is the net gain of ATP when each molecule of glucose is converted to two molecules of pyruvic acid?
- A. Four
- B. Six
- C. Two
- D. Eight
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Answer: B — Six
In glycolysis, glucose to pyruvate conversion: 4 ATP are produced (gross) but 2 ATP are consumed in the initial steps, giving a net gain of 2 ATP molecules.
Q10NEET 2022Energy Release in Fermentation
What amount of energy is released from glucose during lactic acid fermentation?
- A. Approximately 15%
- B. More than 18%
- C. About 10%
- D. Less than 7%
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Answer: C — About 10%
Lactic acid fermentation is an inefficient anaerobic process, releasing less than 7% of the energy content of glucose (compared to about 686 kcal/mol total available via complete aerobic oxidation).

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